Problem: Integer to English Words

Posted by Marcy on February 18, 2015

Question

Convert a non-negative integer to its english words representation. Given input is guaranteed to be less than 231 - 1.

Example 1:

Input: 123
Output: "One Hundred Twenty Three"

Example 2:

Input: 12345
Output: "Twelve Thousand Three Hundred Forty Five"

Example 3:

Input: 1234567
Output: "One Million Two Hundred Thirty Four Thousand Five Hundred Sixty Seven"

Example 4:

Input: 1234567891
Output: "One Billion Two Hundred Thirty Four Million Five Hundred Sixty Seven Thousand Eight Hundred Ninety One"

Solution

TODO

Code

public class Solution {
    private final String[] belowTen = new String[] {"", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"};
    private final String[] belowTwenty = new String[] {"Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"};
    private final String[] belowHundred = new String[] {"", "Ten", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"};
    
    public String numberToWords(int num) {
        if (num == 0) return "Zero";
        return helper(num); 
    }
    
    private String helper(int num) {
        String result = new String();
        if (num < 10) result = belowTen[num];
        else if (num < 20) result = belowTwenty[num -10];
        else if (num < 100) result = belowHundred[num/10] + " " + helper(num % 10);
        else if (num < 1000) result = helper(num/100) + " Hundred " +  helper(num % 100);
        else if (num < 1000000) result = helper(num/1000) + " Thousand " +  helper(num % 1000);
        else if (num < 1000000000) result = helper(num/1000000) + " Million " +  helper(num % 1000000);
        else result = helper(num/1000000000) + " Billion " + helper(num % 1000000000);
        return result.trim();
    }
}

Performance

TODO