Question
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.
According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).”
_______6______
/ \
___2__ ___8__
/ \ / \
0 _4 7 9
/ \
3 5
For example, the lowest common ancestor (LCA) of nodes 2 and 8 is 6. Another example is LCA of nodes 2 and 4 is 2, since a node can be a descendant of itself according to the LCA definition.
Solution
TODO
Code
class Solution {
public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) {
int large = p.val;
int small = q.val;
if(q.val > p.val) {
large = q.val;
small = p.val;
}
if(root.val > large) {
return lowestCommonAncestor(root.left, p, q);
}
else if(root.val < small){
return lowestCommonAncestor(root.right, p, q);
}
return root;
}
}
Performance
TODO