Question
Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
- Integers in each row are sorted from left to right.
- The first integer of each row is greater than the last integer of the previous row.
For example,
Consider the following matrix:
[
[1, 3, 5, 7],
[10, 11, 16, 20],
[23, 30, 34, 50]
]
Given target = 3
, return true
.
Solution
TODO
Code
public class Solution {
public boolean searchMatrix(int[][] matrix, int target) {
int rows = matrix.length;
int cols = matrix[0].length;
int begin = 0;
int end = rows * cols - 1;
while(begin <= end) {
int mid = (begin + end) / 2;
int mid_value = matrix[mid/cols][mid%cols];
if( mid_value == target)
return true;
else if(mid_value < target)
begin = mid+1;
else
end = mid-1;
}
return false;
}
}
Performance
TODO